find the value of sin teeta + cos teeta/ sin teeta - cos teeta
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Answer:
√3 tanA=3sinA
√3sinA/cosA=3sinA
√3=3cosA
cosA =√3/3=1/√3
sinA=√(1-sin²A) =√(1-1/3) =√(2/3)
sinA+cosA=√2/√3 +1/√3=(√2+1) /√3
sinA-cosA=(√2-1) /√3
(sinA+cosA) /(sinA-cosA) =(√2+1) /√3.×√3/(√2-1)
(sinA+cosA) /(sinA-cosA) =(√2+1) /(√2-1)
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