find the value of (sin theta+costheta)^²+(cos theta + sin theta )^²
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Let theta=∅
=(sin∅ + cos∅)²+(cos∅+sin∅)²
=(sin∅)²+(cos∅)²+2×sin∅×cos∅ + (cos∅)²+(sin∅)²+2×cos∅×sin∅
=sin²∅+cos²∅+2sin∅cos∅+cos²∅+sin²∅+2cos∅sin∅
=1 + 1+4sin∅cos∅
=2+2sin∅cos∅
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