CBSE BOARD X, asked by idk21, 1 year ago

Find the value of sin0*sin1*sin2*...... sin89*sin90.

Answers

Answered by Anonymous
10

HOLA MATE..!!

ANSWER:-

As we know that  sin0° = 0,

then,  0× sin2 * sin3... * sin90 = 0

Hence 0 is the required answer.  

hope it helps..!!

Answered by bandameedipravalika0
0

Answer:

Explanation:

Concept:

Here the concept of trigonometry will be used.

Given :

The expression which is given is \sin 0^{\circ} \cdot \sin 1^{0} \sin 2^{0}........... sin 89^{0} \cdot \sin 90^{\circ}$.

To Find:

We have to find the value of above expreesion.

Solution:

According to the Sin Cos Tan Chart , the value of \sin 0^{\circ} is 0 . We know the value is 0 if any number is multiplied by 0 . So we don't need to get the value of \sin 1^{0} \sin 2^{0}........... sin 89^{0} \cdot \sin 90^{\circ}$ . So the product is 0 .

The value of \sin 0^{\circ} \cdot \sin 1^{0} \sin 2^{0}........... sin 89^{0} \cdot \sin 90^{\circ}$  is 0 .

#SPJ3

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