find the value of sin18°
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Let A = 18° Therefore, 5A = 90° ⇒ 2A + 3A = 90˚ ⇒ 2θ = 90˚ - 3A. Taking sine on both sides, we get. sin 2A = sin (90˚ - 3A) = cos 3A. ⇒ 2 sin A cos A = 4 cos^3 A - 3 cos A.
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