find the value of (sin22 1/2 + cos 22 1/2)⁴
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Answer:
answer is......
Step-by-step explanation:
let x=
=(sin22 1/2o cos square 22 1/2o)4
=((sin22 1/2+cos22 1/2)2)2
=(sin square 22 1/2+cos square 22 1/2 +2 sin 2 )
=( 1+sin 45o) square.
therefore
2sintita costita
=( 1+1√2) square =(√2+1/ √2) square
=2+1+2√2/2 =3+2√2/2
tnq......
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