find the value of sin²A+cos²A
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sin²A=hieght²/hypotenuse ²
cos²A=base²/hypotenuse²
(hieght²+base²)/hypotenuse²
hypotenuse²/hypotenuse²
=1
cos²A=base²/hypotenuse²
(hieght²+base²)/hypotenuse²
hypotenuse²/hypotenuse²
=1
Answered by
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Hey there!
sin²A+cos²A = 1 [ ∵ Identity sin²θ + cos²θ = 1]
Where, 'A' are Equal Angles......
HOPE IT HELPED ^_^
sin²A+cos²A = 1 [ ∵ Identity sin²θ + cos²θ = 1]
Where, 'A' are Equal Angles......
HOPE IT HELPED ^_^
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