Question

find the value of sin45°geometrically

Answer 1

hope this answer helps you!!!

Answer 2

Answer:

Hey mate ,

Consider a right angled ΔABC with sides AB = BC = a

and , ∠A = ∠C = 45° , ∠B = 90°

In ΔABC using Pythagoras Theorem we have ,

AC² = AB² + BC²

⇒ AC² = a² + a²

⇒ AC² = 2a²

⇒  AC = a√2

In right angled ΔABC ,

sin 45° = perpendicular / Hypotenuse

            = AB / AC

            = a / √2a

            = 1 / √2

Hope it helps ....