find the value of sin5/cos85
div15:
sin(90-85)/cos85=cos85/cos85=1
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Answered by
2
sin 5/ cos 85
= sin (90-85) / cos 85
= cos 85 / cos 85 ( as cos a = sin 90 - a)
= 1
= sin (90-85) / cos 85
= cos 85 / cos 85 ( as cos a = sin 90 - a)
= 1
Answered by
3
First, sin5 =sin (90-85) = cos85
cos85= cos (90-5) = sin5.
=> sin5/ cos85
=> sin5/cos85
= cos85/Cos85
= 1.
=> sin5/ cos85
=> sin5/sin5
= 1.
sin5/cos85=1
cos85= cos (90-5) = sin5.
=> sin5/ cos85
=> sin5/cos85
= cos85/Cos85
= 1.
=> sin5/ cos85
=> sin5/sin5
= 1.
sin5/cos85=1
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