Math, asked by seniyalakandri, 6 months ago

Find the value of:
(sin60°+cos30°).Sec30°.Cot45°​

Answers

Answered by vipashyana1
1

Answer:

(sin60°+cos30°).sec30°.cot45°

 = ( \frac{ \sqrt{3} }{2}  +  \frac{ \sqrt{3} }{2} ) \times  \frac{2}{ \sqrt{3} }  \times 1

 = ( \frac{ \sqrt{3}  +  \sqrt{3} }{2}  )\times  \frac{2}{ \sqrt{3} }  \times 1

 =  \frac{ 2\sqrt{3} }{2}  \times  \frac{2}{ \sqrt{3} } \times 1

 = 2

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