Question

Find the value of sqrt(3+sqrt(2))

Answer 1

The question should be as follows, if its not then it is unsolvable.$\sqrt{3+2\sqrt2}\\=\sqrt{1^2+(\sqrt2)^2+2\cdot(1)\cdot(\sqrt2)}\\=\sqrt{(1+\sqrt2)^2}\\=1+\sqrt2\\\text{EDIT: I tried other approaches to the problem but I failed}\\\text{so I decided to check for the same in WolframAlpha.}\\\text{It seems that there are no alternate forms for the expression.}$