Question

Find the value of tan 0-..

Answer 1

Step-by-step explanation:

cos 0 = BC/AB

=15/20

=3/4

1+tan^2 0=sec^2 { sec^2 0=1/cos^2 0}

tan^2 0=1/cos^2 0 - 1

=1/(3/4)^2-1

=16/9-1

=7/9

tan 0= √7/3

Answer 2

AC = √(AB² - BC²) = √(20² - 15²) = √(400 - 225) = √175 = 7√5

tanθ = AC/BC = 7√5/15 = 0.882