Question

find the value of tan-1 (tan5)​

Answer 1

Answer:

Let 2π – 5 = θ,  ⇒ 5 = 2π – θ tan 5 = tan (2π – θ)  tan-1 (tan 5) = tan-1 tan (2π – θ)  = tan-1 [-tan θ]  = tan-1 [tan (-θ)] = – θ  = – (2π – 5) = 5 – 2π