Find the value of tan (19π/3)
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tan 19π '/ 3
= tan. 6 1/ 3 π
= tan (.6π + 1 / 3 π)
= tan ( 3 (2π) + 1 / 3π )
= tan 1 / 3π
= tan 1 / 3 * 180
= tan 60
= tan 60 √3
tan 60 = √3
= tan. 6 1/ 3 π
= tan (.6π + 1 / 3 π)
= tan ( 3 (2π) + 1 / 3π )
= tan 1 / 3π
= tan 1 / 3 * 180
= tan 60
= tan 60 √3
tan 60 = √3
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