find the value of tan (22½)°
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a pwer 0 =1.so answer is 1.
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Hey !!!
tan22 ½ ° = ?
•°• tanA/2 = +-√1+tan²A -1 /tanA [•°• A/2 = 22½° ]
•°• tan22½° = +-√1+tan²45° -1 /tan45°
= +- √1+1 - 1 /1
= +-√2-1
°•° 22½ is in first quadrant
so, tan22½° = √2 -1 Answer
~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope it helps you !!!
@Rajukumar111
tan22 ½ ° = ?
•°• tanA/2 = +-√1+tan²A -1 /tanA [•°• A/2 = 22½° ]
•°• tan22½° = +-√1+tan²45° -1 /tan45°
= +- √1+1 - 1 /1
= +-√2-1
°•° 22½ is in first quadrant
so, tan22½° = √2 -1 Answer
~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope it helps you !!!
@Rajukumar111
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