find the value of tan 22 1/2
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22½° lies in the first quadrant.
Therefore, tan 22½° is positive.
For all positive values of the angle A we know that, tan A2A2 = 1−cosA1+cosA−−−−−√1−cosA1+cosA
tan 22½° = 1−cos45°1+cos45°−−−−−−√1−cos45°1+cos45°
tan 22½° = 1−12√1+12√−−−−−√1−121+12, [Since we know that cos 45° = 12√12]
tan 22½° = 2√−12√+1−−−−√2−12+1
tan 22½° = 2√−12√+1⋅2√−12√−1−−−−−−−−−−√2−12+1⋅2−12−1
tan 22½° = (2√−1)22−1−−−−−−√(2−1)22−1
tan 22½° = √2 - 1
Therefore, tan 22½° = √2 - 1
Therefore, tan 22½° is positive.
For all positive values of the angle A we know that, tan A2A2 = 1−cosA1+cosA−−−−−√1−cosA1+cosA
tan 22½° = 1−cos45°1+cos45°−−−−−−√1−cos45°1+cos45°
tan 22½° = 1−12√1+12√−−−−−√1−121+12, [Since we know that cos 45° = 12√12]
tan 22½° = 2√−12√+1−−−−√2−12+1
tan 22½° = 2√−12√+1⋅2√−12√−1−−−−−−−−−−√2−12+1⋅2−12−1
tan 22½° = (2√−1)22−1−−−−−−√(2−1)22−1
tan 22½° = √2 - 1
Therefore, tan 22½° = √2 - 1
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