Question

Find zeroes of px)=x2-5 and Verify the relation​

Answer 1

Answer:

see the attachment...

hope it's help you....

Answer 2

Step-by-step explanation:

GIVEN:-

$p(x) = {x}^{2} - 5$

SOLUTION:-

LET,

$p(x) = {x}^{2} - 5 = 0$

${x}^{2} = 5$

$x =±\sqrt{5}$

$x = \sqrt{5} \: \: or \: \: x = - \sqrt{5}$

NOW LET,

$\alpha=\sqrt{5}$

$\beta=-\sqrt{5}$

We know that,

$\alpha+\beta=\frac{-b}{a}$

and

$\alpha\beta=\frac{c}{a}$

where,

a=1 ,b=0 and c=-5

then,

$\alpha+\beta=\frac{-0}{1}$

$\alpha+\beta=0$

$\alpha\beta=\frac{-5}{1}$

$\alpha\beta=-5$