find the value of tan 2A, if cos3A=sin 45 degrees
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Cos 3A = sin45
so, Cos 3A = sin (90-45)
Cos 3A = Cos45
so, 3A = 45
so, A = 15°
So, tan 2A = tan 2*15 = tan30° = 1/√3
so, Cos 3A = sin (90-45)
Cos 3A = Cos45
so, 3A = 45
so, A = 15°
So, tan 2A = tan 2*15 = tan30° = 1/√3
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