find the value of tan 2A, if cos3A =sin45°
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shivakrishna933:
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✔✔✔✔
cos 3A = sin 45°
➡cos 3A=1/√2
➡cos 45°=1/√2
➡3A=45°
➡A=15°...............(1)
tan 2A
=tan30°
=1/√3
.....................
cos 3A = sin 45°
➡cos 3A=1/√2
➡cos 45°=1/√2
➡3A=45°
➡A=15°...............(1)
tan 2A
=tan30°
=1/√3
.....................
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