Find the value of-
tan(90-theta)cot theta- sec (90-theta)cosec theta + 3(cot^2 67- sec^2 63) / cot 26 cot 41 cot 45 cot 49 cot 64
vikaskumar0507:
here sec^2 23 or sec^2 63.
Answers
Answered by
3
LET theta be Ф & NUMBERS THAT ARE UNDERLINED ARE SOLVED IN NEXT LINE.
QUESTION: tan(90-Ф)cotФ - sec(90-Ф) cosecФ +3(cot² 67 - sec² 63) / cot 26 cot 41 cot 45 cot 49 cot 64
SOLUTION: cotФ cotФ - cosecФ cosecФ +3(cot² 67 - sec² 63) / cot(90 - 64) cot(90 -49) cot 45 cot 49 cot 64
cot²Ф - cosec²Ф + 3(cot² 67 - sec² 63) / tan 64 cot64 *1*cot 49 tan 49
-1 +3(cot² 67 - sec² 63) / 1*1*!
-1 +3(cot² 67 - sec² 63 )
-1 +3cot² 67 - 3sec² 63
**//THIS QUESTION CAN NOT BE FURTHER SOLVED.THE VALUE 67 OR 63 MUST BE CHANGED OTHERWISE IT CAN NOT BE SOLVED//**
QUESTION: tan(90-Ф)cotФ - sec(90-Ф) cosecФ +3(cot² 67 - sec² 63) / cot 26 cot 41 cot 45 cot 49 cot 64
SOLUTION: cotФ cotФ - cosecФ cosecФ +3(cot² 67 - sec² 63) / cot(90 - 64) cot(90 -49) cot 45 cot 49 cot 64
cot²Ф - cosec²Ф + 3(cot² 67 - sec² 63) / tan 64 cot64 *1*cot 49 tan 49
-1 +3(cot² 67 - sec² 63) / 1*1*!
-1 +3(cot² 67 - sec² 63 )
-1 +3cot² 67 - 3sec² 63
**//THIS QUESTION CAN NOT BE FURTHER SOLVED.THE VALUE 67 OR 63 MUST BE CHANGED OTHERWISE IT CAN NOT BE SOLVED//**
Similar questions