Question

find the value of Tan theta​

Answer 1

Step-by-step explanation:

secthita = 13\5

h\b = 13\5

p^2 = 144

p= 12

now tanthita = p\b

= 12\5

hope it's help you ✌✌✌✌

Answer 2

Finding value:

Step-by-step explanation:

$\ Given \ value:\\\\\sec \theta= \frac{13}{5}\\\\\ find:\\\\\tan \theta =?\\\\\ Solution:\\\\\therefore \sec^2\theta-\tan^2\theta= 1\\\\\tan^2\theta= \sec^2\theta -1\\\\\sec\theta= \frac{13}{5}\\\\\sec^2\theta= \frac{165}{25}\\\\\tan^2\theta=\frac{165}{25}- 1\\\\\tan^2\theta=\frac{165-25}{25}\\\\\tan^2\theta=\frac{144}{25}\\\\\tan^2\theta=(\frac{12}{5})^2\\\\\tan\theta= \frac{12}{5}$

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