Find the value of tan15º tan 30° tan 45º tan60° tan75°
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Let put every ratio in such a manner that the sum of ratio will be 90 tan15° tan75 tan30° tan60° tan45 tan(90-75) tan75 tan(90-60) tan 60 tan45
So
* (tan(90-A)=cotA]
cot75°tan75° cot60'tan 60'tan 45º 1/tan 75 tan 75 1/tan60 tan60° tan45 "[cotA=1/tanA] [tan45°-1]" So the solution to this is 1 .
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tanA=1/cotA
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