Question

find the value of tanA\1+secA-tanA\1-secA​

Answer 1

Answer:

Use the Attached file for solution

Step-by-step explanation:

It will must help you

Answer 2

Answer:

$\frac{tanA}{1 + secA} - \frac{tanA}{1 - secA} \\ \\ = tanA( \frac{1}{1 + secA } - \frac{1}{1 - secA} ) \\ \\ = tanA( \frac{1 - secA - 1 - secA}{1 - {sec}^{2} A} )\\ \\ = tanA( \frac{ - 2secA}{ - {tan}^{2}A } ) \\ \\ = 2 \frac{secA}{tanA} \\ \\ = 2 \: \frac{1}{cosA} . \frac{cosA}{sinA} \\ \\ = 2cosecA$