Question

find the value of
$3 \sqrt{726 } \: - 3 \sqrt{27} \\ 3 \sqrt{512 \: \: + 3 \sqrt{343} }$
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Answer 1

Answer:

$\frac{ \sqrt[3]{729} - \sqrt[3]{27} }{ \sqrt[3]{512} + \sqrt[3]{343} } \\ \\ \frac{9 - 3}{8 + 7} \\ \\ \frac{6}{15} \\ \\ \frac{2}{5}$

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Answer 2

Answer:

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Step-by-step explanation:

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