Question

find the value of.
${ \cos(48) }^{2} + { \cos(12) }^{2}$
​

Answer 1

Cos(48)² + Cos(12)²

= 0.4097847754 + 0.7120895037

= 1.1218742791

Answer 2

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cos48 = 0.6691 0.67 = 2/3 (approx)

SO, cos²48° = {2/3)²

= 4/9

and cos12° = 0.9781

now, cos²12° = (0.9781)² = 0.9566

= 0.96 96/100

= 24/25.

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