Question

Find the value of
$\frac{1}{1 + \sqrt{2} }$
​

Answer 1

$\frac{1}{1 + \sqrt{2} }$

$\frac{1}{1 + \sqrt[]{2} } + \frac{1 - \sqrt{2} }{1 - \sqrt{2} }$

$\frac{1 - \sqrt{2} }{(1) {}^{2} - ( \sqrt{2} ) {}^{2} }$

$\frac{1 - \sqrt{2} }{1 - 2}$

$\frac{1 - \sqrt{2} }{ - 1}$

It's the correct answer mark brainiest please

Answer 2

Answer:

Step-by-step explanation:

0.4142135624 or -1+root2