Math, asked by shahin5, 1 year ago

find the value of
sin {15}^{0} cos {75}^{0}

Answers

Answered by Akash8840
1
→Sin15°cos75°
→Sin(90°-15°) cos75°
→Cos75cos75°
→Cos²75°
Answered by Deepsbhargav
1
hey here is your answer

sin15.cos75= sin15.cos(90-15)
= sin15.sin15
=(sin15)2
= ((root3-1)/2root2)2
=(3+1-2root3)/8
= (4-2root3)/8
= (2-root3)/4

I hope it will help you
Attachments:

Deepsbhargav: if you satisfied to my answer plz it's Mark as brainliest
shahin5: can u plzz help me for another que
Deepsbhargav: yes
Deepsbhargav: sure
Deepsbhargav: ask your question
shahin5: my 1st top question which i asked
Deepsbhargav: where
Similar questions