Question

find the value of
$\sqrt{6 + \sqrt{6 + \sqrt{6....} } }$
Is​

Answer 1

Answer:

6

Step-by-step explanation:

$x = \sqrt{6 \sqrt{6 \sqrt{6......... \infty } } } \\ x = \sqrt{6x} \\ {x}^{2} = 6x \\ x = 6$

hope it helps............................