Question

find the value of
$( {x}^{3} - 3) \times ( {x}^{2} + 1)$
when x = -1
​

Answer 1

$\huge\mathfrak{\underline{Solution:-}}$

We have to find the value of

$\sf \bullet (x{}^{3}-3)\times (x{}^{2}+1)\\ \\ \sf\bullet when x=(-1)$

Now put the value of x

$\sf\implies x{}^{2}-3\times x{}^{2}+1\\ \\ \sf\implies (-1){}^{3}-3\times (-1){}^{2}+1\\ \\ \sf\implies (-1)-3\times 1+1\\ \\ \sf\implies -4\times 2\\ \\ \sf\implies (-8)$

$\boxed{\sf{(x{}^{3}-3)\times( x{}^{2}-1)=(-8)}}$

Answer 2

Answer:

$\huge\mathfrak\red{Ello}$

$( {x}^{3} - 3) \times ( {x}^{2} + 1) \\ \\ by \: putting \: value \: of \: x \: which \: is \: equal \: to \: - 1 \\ \\ then \\ \\ ( { - 1}^{ 3 } - 3) \times ( { - 1}^{2} + 1) \\ \\( - 1 - 3) \times ( 1 + 1) \\ \\ - 4 \times 2 \\ \\ - 8$

$\huge\mathfrak\green{Thanks}$