Question

find the value of
${x}^{3} - {x}^{2} + 2x +4 when x=1+√3 i \ \textless \ br /\ \textgreater$
​

Answer 1

Answer:

plz make it clear

plz

then only i can answer it

Answer 2

$x^3-x^2+2x+4\\\\=x^2(x-1)+2x-2+6\\\\=x^2(x-1)+2x(x-1) +6 \\\\=(x-1)(x^2+2)+6\\\\=(1+\sqrt{3} i-1) [ (1+\sqrt{3i})^2+2]+6\\\\= \sqrt{3}i [ 1+( \sqrt{3}i)^2+2 \sqrt{3}+2]+6\\\\=\sqrt{3}i (1-3+2\sqrt{3}i+2)+6\\\\\bf= \sqrt{3}i(2 \sqrt{3}i)+6\\\\=-6+6\\\\=0$