Math, asked by taetae021, 10 months ago

find the value of the above logarithm question.

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Answers

Answered by 217him217
1

Answer:

2(loga + loga² + loga³ + ..... +loga^m)

= 2(loga + 2loga + 3loga + .... + mloga)

=2loga (1 + 2 + 3 +......+ m)

we have formula for add n no. in AP = n(n+1)/2

=>2loga[m(m+1)/2]

=>loga(m(m+1))

Answered by anuragravi976345
1

Answer:

the value of abovelogarithm is

Step-by-step explanation:

log a (m(m+1)

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