find the value of the above logarithm question.
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Answer:
2(loga + loga² + loga³ + ..... +loga^m)
= 2(loga + 2loga + 3loga + .... + mloga)
=2loga (1 + 2 + 3 +......+ m)
we have formula for add n no. in AP = n(n+1)/2
=>2loga[m(m+1)/2]
=>loga(m(m+1))
Answered by
1
Answer:
the value of abovelogarithm is
Step-by-step explanation:
log a (m(m+1)
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