Question

Find the value of




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Answer 1

Given,

{x}^{3} +  {y}^{3} - 12xy + 64 \\  \\   =  >  { x}^{3} +  {y}^{3} + (4 {)}^{3}  - 3(4xy) \\  \\  =  > (x + y + 4)( {x}^{2} +  {y}^{2} +  {4}^{2} - xy - 4y - 4x) \\  \\  =  > x + y =  - 4 \\  \\  =  > ( - 4 + 4)( {x}^{2} +  {y}^{2} +  {4}^{2}  - xy - 4y - 4x) \\  \\  =  > (0)( {x}^{2} +  {y}^{2} +  {4}^{2}  - xy - 4y - 4x) \\  \\  = 0    

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