Question

Find the value of the discriminant of the following equation 10x² + x = 1.​

Answer 1

Step-by-step explanation:

10x² + x -1 = 0

discriminant = b^2-4ac

(1)^2-4(10)(-1)

= 1+40

= 41

Answer 2

Answer:

Converting the eq in std form,

10x² + x - 1 = 0

then discriminant b² - 4ac

= (1)² - 4 (10)(-1)

= 1 + 40

= 41

hence we can say that roots are real and unequal