Question

Find the value of the discriminant of the following equation
(1) 10x2 +x = 1
(Answer : 41)​

Answer 1

Quadratic Equation

A quadratic equation in a variable $x$ is an equation which is of the form $ax^2 + bx + c = 0$ where constants a, b and c are all real numbers and $a \neq 0.$

In case of a quadratic equation $ax^2 + bx + c = 0$ the expression $b^2 - 4ac$ is called the discriminant.

Let's first solve the given equation!

$\implies 10x^2 + x = 1 \\ \\ \implies 10x^2 + x - 1 = 0$

Now, comparing the given equation with the standard form of quadratic equation, we get:

$\qquad a = 10, \: b = 1, \: c = -1$

Now using the discriminant formula and solving the equation, we get:

$\implies {1}^{2} - 4 \times 10 \times (-1) \\ \\ \implies 1 - 4 \times 10 \times (-1) \\ \\ \implies 1 - (-40) \\ \\ \implies 1 + 41 \\ \\ \implies \boxed{41}$

Hence, the required answer is 41.

Answer 2

Step-by-step explanation:

given :

• Find the value of the discriminant of the following equation

to find:

• 10x2 +x = 1 = ?

• 10x2 +x = 1 = ?

formula :

• ax2 + bx + c = 0

solution :

• 1² +4 × 10 × 1

• 1+ 4 x 10 x 1

• 1 +40

• = 41