Question

Find the value of the expression (36x²+25y²‐60xy,when x=2/3 and y=1/5​

Answer 1

S O L U T I O N :

$\underline{\bf{Given\::}}$

36x² + 25y² - 60xy when the value of x = 2/3 & y = 1/5

$\underline{\bf{Explanation\::}}$

$\longrightarrow\tt{36x^{2} + 25y^{2} - 60xy}$

$\longrightarrow\tt{36\bigg(\dfrac{2}{3} \bigg)^{2} + 25\bigg(\dfrac{1}{5}\bigg)^{2} - 60\times \dfrac{2}{3} \times \dfrac{1}{5} }$

$\longrightarrow\tt{36\times \dfrac{2}{3} \times \dfrac{2}{3} + 25\times \dfrac{1}{5}\times \dfrac{1}{5} - 60\times \dfrac{2}{3} \times \dfrac{1}{5} }$

$\longrightarrow\tt{36\times \dfrac{4}{9} + 25\times \dfrac{1}{25} - 60\times \dfrac{2}{15} }$

$\longrightarrow\tt{ \dfrac{144}{9} +\dfrac{25}{25} - \dfrac{120}{15} }$

$\longrightarrow\tt{ \cancel{\dfrac{144}{9}} + \cancel{\dfrac{25}{25}} - \cancel{\dfrac{120}{15} }}$

$\longrightarrow\tt{16 + 1 - 8}$

$\longrightarrow\tt{17-8}$

$\longrightarrow\bf{9}$

Thus,

The value of the expression will be 9 .