Question

Find the value of the expression a² – 2ab + b² for a = 1, b = 1
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Answer 1

SOLUTION :-

TO DETERMINE :-

The value of the expression

$\sf{ {a}^{2} - 2ab + {b}^{2} }$ for a = 1 , b = 1

EVALUATION :-

PROCESS : 1

Here the given expression is

$\sf{ {a}^{2} - 2ab + {b}^{2} }$

Putting a = 1 & b = 1 we get the value of the expression

$= \sf{ {(1)}^{2} - 2.1.1 + {(1)}^{2} }$

$= \sf{ 1 - 2 + 1 }$

$\sf{ = 0}$

PROCESS : 2

USING IDENTITY

We are aware of the identity that

$\sf{ {a}^{2} - 2ab + {b}^{2} } = {(a - b)}^{2}$

Hence the value of the expression

$= \sf{ {a}^{2} - 2ab + {b}^{2} }$

$= \sf{ {(a - b)}^{2} }$

$\sf{ = {(1 - 1)}^{2} }$

$\sf{ = {(0)}^{2} }$

$= 0$

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Answer 2

Answer:

Answer is 0

Step-by-step explanation:

Please refer the attachment for steps

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