Question

Find the value of the following expressions at a = 1 and b = –2


(i) a2 + b2 + 3ab ​

Answer 1

Answer:

-1

Step-by-step explanation:

${a}^{2} + {b}^{2} + 3ab \\ = {1}^{2} + ( - 2)^{2} + 3 \times 1 \times ( - 2) \\ = 1 + 4 - 6 = - 1$

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Answer 2

Answer:

2×1+2×(-2)+3×1×(-2)

2-4-6

-8

Step-by-step explanation:

-8 is your answer.