Math, asked by gomtirai3114, 2 months ago

find the value of the following q.no d to j plz​

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Answered by HolyGirl
40

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(d) \Large(\frac{1}{2})^{-4}

\Large=(\frac{2}{1})^4

\Large=(2)^4

=\fbox{16} \\ \\

(e) \Large(\frac{2}{3})^{-5}

\Large=(\frac{3}{2})^5

=\fbox{\frac{243}{32}}\\ \\

(f) \Large(\frac{-3}{5})^{-2}

\Large=(-\frac{5}{3})^2

=\fbox{\frac{25}{9}}\\ \\

(g) \Large(\frac{3}{-7})^{-3}

\Large=(\frac{-7}{3})^3

=\fbox{\frac{343}{27}}\\ \\

(h) \Large(\frac{-3}{4})^{-4}

\Large=(\frac{4}{3})^4

=\fbox{\frac{256}{81}}\\ \\

(i) \Large(\frac{2}{5})^{-3}×(\frac{2}{3})^{-2}

\Large=(\frac{5}{2})^3×(\frac{3}{2})^2

\Large=(\frac{125}{8})×(\frac{27}{8})

=\fbox{\frac{3375}{64}}\\ \\

(j) \Large(\frac{-1}{4})^{-3}÷(\frac{3}{8})^{-2}

\Large=(\frac{4}{-1})^3÷(\frac{8}{3})^2

\Large=(\frac{64}{1})÷(\frac{64}{9})

\Large=(\frac{64}{1})×(\frac{9}{64})

\large=\fbox{9}\\ \\

Answered by sanaykh123
2

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