Question

find the value of the following qn
sin(4530) its urgent plsss

Answer 1

Answer:

The value of $\sin 4530^{\circ}$  is -0.5 or$\frac{-1}{2}$.

To find:

The value of $\sin 4530^{\circ}$

Solution:

Here $\theta = 4530 ^ { \circ }$

Separate the $\theta$ into solvable terms

Hence, the nearer value when we divide 4530° by 180° is 25.

Hence, we can consider

$\begin{aligned} 4530 ^ { \circ } & = 25 \times 180 ^ { \circ } + 30 ^ { \circ } = 25 \pi + 30 ^ { \circ } \\\\ & \therefore \sin 4530 ^ { \circ } = \sin \left( 25 \pi + 30 ^ { \circ } \right) \end{aligned}$

Here $\pi =180^{\circ}$

WKT, the value of $\sin \pi =0$, so the value of $\sin 25\pi=0$

$\sin 4530 ^ { \circ } = \sin \left( 30 ^ { \circ } \right)$

[since this 30 degrees lies in the third quadrant, hence the answer will be negative]

[Note that a whole unit circle has 360 degrees]

$=\sin 30^{\circ}= \frac{-1}{2}$

Answer 2

sin4530°=sin(50×90°+30°)

= - sin30°

= - 1/2