Question

Find the value of the following with the help of log table :
V102.5 (0.0025) .​

Answer 1

Answer:

Let x=5872×0.058

Taking log both sides, we have

logx=log(5872×0.058)

logx=log5872+log0.058(∵logab=loga+logb)

logx=log(58.72×10

2

)+log(58×0

−3

)

logx=log58.72+2+log58−3(∵log10=1)

⇒1+logx=log58.72+log58

Using log table, we get

log58.72=1.77

log58=1.76

∴1+logx=1.77+1.76

⇒logx=3.53−1

⇒logx=2.53

⇒x=Antilog(2.53)=338.84

Therefore,

5872×0.058≈338.84