Question

Find the value of the given expression.

Answer 1

Answer:

1

Step-by-step explanation:

*While multiplying, if the bases have same value, then indices will be added.

*While dividing, if the bases have same value, then index of denominator will be subtracted from the index of the numerator.

So, first of all with these theories in mind, let's see whether we can write 9 with base 3 since other two already has 3 as bases.

9 can be written as $3^{2}$ (3 x 3)

So, $3^{2}$ x $3^{n-1}$ ÷$3^{n+1}$

First we can solve the numerator.

if we add the indices,

2 + n-1

$3^{2+n-1}$

Next we can subtract the index of denominator from the numerator

So,

2+n-1 - (n+1)

=2+n-1-n-1

=2-2

=0

So, the answer is $2^{0}$

$2^{0}$ = 1