Find the value of the given expressions when a=0, b=-1, c=1
2) a²+2ab+b³
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Answer:
the answer is 4
Step-by-step explanation:
i got 4 by knowing 0²is still 0 then you add 1 which is b then b³ which is the same as 1×3 so then you add 3 to 1 there you go you have 4
im not 100% sure if this is the right answer as i havent done algerbra in a while but it definatley should be right
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hope this will help you. thank you
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