Question

Find the value of the k for the quadritic equation 2x square+kn+3=0 has two equal root​

Answer 1

Answer:

k = $\sqrt{24$

Step-by-step explanation:

2$x^{2}$ + kx + 3 = 0

a = 2, b = k, c = 3

Using delta:

x = $b^{2}$ - 4 a*c

x= $k^{2}$ - 4 (2)(3)

x=  $k^{2}$ - 24

0=  $k^{2}$ - 24

$k^{2}$ = 24

k  =  $\sqrt{24}$