Math, asked by Harshly, 1 year ago

find the value of the missing variate for the following distribution whose mean is 10:
Variate(xi) 5, 7, 9, 11,--- 15, 20
frequency fi 4, 4, 4, 7, 3, 2, 1

Answers

Answered by Incredible29
6
Hey
Here's your answer

The frequencies are 4, 4, 4, 7, 3, 2, 1
The variates are 5, 7, 9, 11,x, 15, 20
So number of terms are 4+ 4+ 4+ 7+ 3+ 2+ 1
= 25.

The sum of all the observations are
= (5*4)+(7*4)+(9*4)+(11*7)+(3*x)+(2*15)+(1*20)
= 20+28+36+77+3x+30+20.
= 211+3x

Mean of the observations is 10.

So total of the observations is = 25*10 = 250

ATQ,
250 = 211 + 3x
=> 39 = 3x
=> 11 = x (Answer)

Hope it helps!!

Harshly: Intelligent question
Hybridization
sp
sp2
sp3
sp3d
sp3d2
sp3d3
Formula
I=GA+1/2(V:E-V-C)

GA=Number of group atom attached to the central atom

VE= number of valence electron present in central atom

V= valency of central atom

C= charge present on central atom

1 .Question.[Ni(CN)4]--
2.Question [Ni(NH3)4]2+
3.Question [Cu(CN)4]--
4.Question [Fe(CN)6]----
5.Question [Ptcl4]--
Incredible29: sorry i hv no idea about the question
Harshly: Intelligent question
Hybridization
sp
sp2
sp3
sp3d
sp3d2
sp3d3
Formula
I=GA+1/2(V:E-V-C)

GA=Number of group atom attached to the central atom

VE= number of valence electron present in central atom

V= valency of central atom

C= charge present on central atom

1 .Question.[Ni(CN)4]--
2.Question [Ni(NH3)4]2+
3.Question [Cu(CN)4]--
4.Question [Fe(CN)6]----
5.Question [Ptcl4]--
Harshly: ok
Similar questions