Math, asked by ishi2918, 1 year ago

Find the value of the polynomial 16x^2-4x+1 when x=2/4

Answers

Answered by shreya0676
1

Answer:

16x^2-4x+1

Put x=2/4, or we can say 1/2

16*(1/2)^2-4(1/2)+1

16*1/4-4*1/2+1

16/4-4/2+1

4-2+1

=3

Hope you get it...

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