Find the value of the polynomial 2x3-7x2+x+5 when x=1
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Answer:
-2 is your answer
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Answer:
P(x) =2x³-7x²+x+5
P(1)=2(1)³-7(1)²+1+5
P(1)=2-7+1+5
P(1)=8-7
P(1)=1
Therefore the value of 2x³-7x²+x+5 is 1
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