The first and last terms of an A.P. are 1 and 11. If the sum of its terms is 36, then the number of terms will be
(a) 5
(b) 6
(c) 7
(d) 8
Answers
Answered by
57
Answer:
The number of terms will be 6 .
Among the given options option (b) is correct.
Step-by-step explanation:
Given :
first term , a1 = 1, last term , an = l = 11 = l , Sn = 36
By using the formula ,Sum of nth terms , Sn = n/2 [a + l]
Sn = n/2 [1 + 11]
36 = n/2 × (12)
36 = 6n
n = 36/6
n = 6
Hence, the number of terms will be 6 .
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Answered by
50
Answer : Numbers of terms = 6
EXPLANATION:
Given,
The first term of an AP = a = 1
The last term of an AP = an = 11
Sum of the terms = 36
We know that,
Sum of terms in an AP = n/2 [a + an]
36 = n/2 [a + an]
36 = n/2 [1 + 11]
36 = n/2 [12]
=> 36 = 6n
=> n = 36/6
=> n = 6
Therefore, there are 6 terms in the AP.
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