Question

Find the value of the polynomial f(y) =6y- 3y2+ 3 at
(i) y = 1 (ii) y = –1 (iii) y = 0

Answer 1

Hi pupil here's your answer ::

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please see the attached answer

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hope that it helps. . . .

Answer 2

Answer:

(i) 6

(i) -6

(i) 3

Step-by-step explanation:

In the question

$F(y) = 6y\ -\ 3y^{2}\ +\ 3$

(i) y = 1  (given)

Put the value of y in F(y)

$F(1) = 6(1)\ -\ 3(1)^{2}\ +\ 3$

  = 6 - 3 + 3

  = 6 (Answer)

(ii) y = - 1

Put the value of y in F(y)

$F(-1) = 6(-1)\ -\ 3(-1)^{2}\ +\ 3$

    = - 6 - 3 + 3

    = - 6 (Answer)

(iii) y = 0

Put the value of y in F(y)

$F(0) = 6(0)\ -\ 3(0)^{2}\ +\ 3$

    = 0 - 0 + 3

    = 3 (Answer)