in the given figure st parallel to rq , ps=3 cm and sr=4 cm , find the ratio of the area of triangle pst to the area of triangle prq .
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Given
ST || RQ
PS= 3 cm
SR = 4cm
proof
ar(∆PST) /ar(∆PRQ)= (PS)²/(PR)²
ar(∆PST) /ar(∆PRQ)= 3²/(PS+SR)²
ar(∆PST) /ar(∆PRQ)= 9/(3+4)²= 9/7²=9/49
Hence, the required ratio ar(∆PST) :ar(∆PRQ)= 9:49
Given
ST || RQ
PS= 3 cm
SR = 4cm
proof
ar(∆PST) /ar(∆PRQ)= (PS)²/(PR)²
ar(∆PST) /ar(∆PRQ)= 3²/(PS+SR)²
ar(∆PST) /ar(∆PRQ)= 9/(3+4)²= 9/7²=9/49
Hence, the required ratio ar(∆PST) :ar(∆PRQ)= 9:49
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