English, asked by SakshiT7, 1 year ago

Find the range of f(x)= x+2/2x^2+3x+6

Answers

Answered by MANKOTIA

0

put f(x)=y
x+2)/2x^2+3x+6=y
x+2=2x^2 ×y+3yx+6y.
2yx^2+(3y-1)x+6y-2=0

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