Question

Find the value of the polynomial p (x)= x^3-3x^2-2x+6 at x= Root 2

Answer 1

Putting x=√2
P(√2)=(√2)^3-3(√2)^2-2(√2)+6
=>2√2-6-2√2+6
=>0

Answer 2

Hello Dear !
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p(x) = x³ - 3x² - 2x + 6
Given : X = √2
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Solution : 
put x = √2 in p(x) 
we get 
p(√2) = (√2)³ - 3 X (√2)²-2√2 + 6 
         = 2√2 - 3 X 2   -2√2  + 6
         = 2√2 - 6 +6 - 2√2
         = 0
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